x^2+3x-5-(4x-5)=x^2-x-10

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Solution for x^2+3x-5-(4x-5)=x^2-x-10 equation: 



x^2+3x-5-(4x-5)=x^2-x-10

We move all terms to the left:

x^2+3x-5-(4x-5)-(x^2-x-10)=0

We get rid of parentheses

x^2-x^2+3x-4x+x+5+10-5=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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